(7x/x+1)^2-3(7x/x+1)=18

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Solution for (7x/x+1)^2-3(7x/x+1)=18 equation:


D( x )

x = 0

x = 0

x = 0

x in (-oo:0) U (0:+oo)

((7*x)/x+1)^2-(3*((7*x)/x+1)) = 18 // - 18

((7*x)/x+1)^2-(3*((7*x)/x+1))-18 = 0

((7*x)/x+1)^2-3*((7*x)/x+1)-18 = 0

64-3*8-18 = 0

64-3*8-18 = 0

40-18 = 0

22 = 0

22 = 0

x belongs to the empty set

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